# Palindrome Number without converting the integer to a string

Given an integer `x`, return `true` if `x` is palindrome integer.

An integer is a palindrome when it reads the same backward as forward.

• For example, `121` is a palindrome while `123` is not.

Example 1:

```Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.
```

Example 2:

```Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
```

Example 3:

```Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
```

Constraints:

• `-231 <= x <= 231 - 1`

Follow up: Could you solve it without converting the integer to a string?

### Solution 1:

``return False if x < 0 else x == int(str(x)[::-1])``

### Solution 2:

``````class Solution:
def isPalindrome(self, x):
"""
:type x: int
:rtype: bool
"""
if x < 0:
return False
str_1 = str(abs(x))
str_2 = str_1[::-1]
if str_1 == str_2:
return True
else:
return False``````