Given an integer x
, return true
if x
is palindrome integer.
An integer is a palindrome when it reads the same backward as forward.
- For example,
121
is a palindrome while123
is not.
Example 1:
Input: x = 121 Output: true Explanation: 121 reads as 121 from left to right and from right to left.
Example 2:
Input: x = -121 Output: false Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10 Output: false Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
Constraints:
-231 <= x <= 231 - 1
Follow up: Could you solve it without converting the integer to a string?
Table of Contents
Solution 1:
return False if x < 0 else x == int(str(x)[::-1])
Solution 2:
class Solution:
def isPalindrome(self, x):
"""
:type x: int
:rtype: bool
"""
if x < 0:
return False
str_1 = str(abs(x))
str_2 = str_1[::-1]
if str_1 == str_2:
return True
else:
return False
return False if x < 0 else x == int(str(x)[::-1])
class Solution:
def isPalindrome(self, x):
"""
:type x: int
:rtype: bool
"""
if x < 0:
return False
str_1 = str(abs(x))
str_2 = str_1[::-1]
if str_1 == str_2:
return True
else:
return False